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First solution in Creative category for The Angles of a Triangle by mijalskihubert
import math
def checkio(a, b, c):
ang1=0
ang2=0
ang3=0
print(a+b,">",c,c+b,a+c)
if(a+b>c and c+b>a and a+c>b):
#nowka=max(a,b,c);
cosa=((a*a)-(b*b)-(c*c))/(-2*b*c)
cosb=((b*b)-(a*a)-(c*c))/(-2*a*c)
ang1=round(math.degrees(math.acos(cosa)),0)
ang2=round(math.degrees(math.acos(cosb)),0)
ang3=180-ang1-ang2
ANGLE1=max(ang1,ang2,ang3)
ANGLE3=min(ang1,ang2,ang3)
ANGLE2=ang1+ang2+ang3-ANGLE1-ANGLE3
return[ANGLE3,ANGLE2,ANGLE1]
else:
return [0,0,0]
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(4, 4, 4) == [60, 60, 60], "All sides are equal"
assert checkio(3, 4, 5) == [37, 53, 90], "Egyptian triangle"
assert checkio(2, 2, 5) == [0, 0, 0], "It's can not be a triangle"
Nov. 3, 2016
