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First solution in Clear category for The Angles of a Triangle by KarolinaK
import math
def checkio(a, b, c):
co =0
t=[]
if(a+b>c and b+c>a and c+a>b):
co=(a**2)/((-2)*c*b)+b/(2*c)+c/(2*b)
print(math.degrees(math.acos(co)))
t.append(round(math.degrees(math.acos(co)),0))
co=(b**2)/((-2)*a*c)+c/(2*a)+a/(2*c)
t.append(round(math.degrees(math.acos(co)),0))
co=(c**2)/((-2)*a*b)+b/(2*a)+a/(2*b)
print(co)
t.append(round(math.degrees(math.acos(co)),0))
t.sort()
print(t)
return t
else:
return [0,0,0]
#replace this for solution
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio(4, 4, 4) == [60, 60, 60], "All sides are equal"
assert checkio(3, 4, 5) == [37, 53, 90], "Egyptian triangle"
assert checkio(2, 2, 5) == [0, 0, 0], "It's can not be a triangle"
Oct. 17, 2016