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First solution in Clear category for Three Words by wolicki.mikolaj
# migrated from python 2.7
def checkio(words):
w=words.split()
wynik=True
pom=0
if len(w)<3:
return False
for i in w:
d=""
d=i
if d.isalpha()==True:
pom=pom+1
if pom==3:
return True
print(pom)
else:
pom=0
print("kasuje")
if pom>=3:
return True
else:
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("one two 3 four five six 7 eight 9 ten eleven 12") == True, "Hello"
#assert checkio(u"He is 123 man") == False, "123 man"
#assert checkio(u"1 2 3 4") == False, "Digits"
#assert checkio(u"bla bla bla bla") == True, "Bla Bla"
#assert checkio(u"Hi") == False, "Hi"
Oct. 13, 2016
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