1-liner: 68 chars, nickie's improved creative solution for Three Words by przemyslaw.daniel - python coding challenges

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1-liner: 68 chars, nickie's improved solution in Creative category for Three Words by przemyslaw.daniel

checkio=lambda s:'www'in''.join('wd'[x.isdigit()]for x in s.split())

Oct. 16, 2017

Comments:

emo_code on Feb. 1, 2018, 6:14 p.m.
what is www and wd?

przemyslaw.daniel on Feb. 1, 2018, 7:18 p.m.
'w' represents word or more preciesly somthing which is not a digit. This could be any letter but you have to remember to replace it everywhere. Let's take example input 'a b c 123'. 1) first step is to split it: ['a', 'b', 'c' '123'] 2) for every element check whether these are all digits: [False, False, False, True] 3) beacuse bool is a subclass of int True is equal to 1, False to 0. This is used to extract 'w' or 'd' letter from 'wd' based of index: ['w', 'w', 'w', 'd'] 4) all we have do now is to join it and check if 'www' is in 'wwwd' which is true in this case

CDG.Axel on March 23, 2023, 10:41 a.m.
Same length but without indexing ) <pre class='brush: python'>checkio=lambda s:'111'in''.join(str(+x.isalpha())for x in s.split()) </pre>

Strings and Integers

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