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First solution in Clear category for Three Words by Rafal__Kotas
def checkio(words):
p = False
x = 0
numb = 0
napis = words.split(" ")
for i in range (len(napis)):
w=napis[i]
if(len(napis[i]) > 0):
if (w[numb]== '0' or w[numb]== '1' or w[numb]== '2' or w[numb]== '3' or w[numb]== '4' or w[numb]== '5' or w[numb]== '6' or w[numb]== '7' or w[numb]== '8' or w[numb]== '9'):
x = 0
else:
x = x + 1
if(x==3):
p = True
return p
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Nov. 1, 2016
