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First solution in Clear category for Three Words by Rafal.U
def checkio(words):
sentence = words.split(' ')
print(sentence)
licznik = 0
for i in range(0,len(sentence)):
n = len(sentence)
if (sentence[i].isalpha()):
print(sentence[i])
licznik += 1
x = licznik
if x >= 3:
return True
else:
licznik = 0
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Oct. 26, 2016