First uncategorized solution for Three Words by PrettyLiza - python coding challenges

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First solution in Uncategorized category for Three Words by PrettyLiza

def checkio(words): 
    words=words.split(' ') 
    for s in range(len(words)-2): 
        if words[s].isalpha() and words[s+1].isalpha() and words[s+2].isalpha() : 
            return (True) 

    return (False)

Oct. 15, 2015

Comments:

walkingpendulum on Oct. 16, 2015, 5:07 p.m.
<p>а если вас попросят написать код, который будет проверять не 3 слова, а 2015, что вы будете делать, писать 2014 операторов and? подумайте немного и перепишите. не забывайте насчет пробелов вокруг операций сложения и присваивания.</p>

Strings and Integers

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