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First solution in Clear category for Three Words by PawelBubak
def checkio(words):
count = 0
stop = 0
for w in words.split():
if w.isdigit():
count = 0
elif w.isalpha():
count = count + 1
if count==3:
stop=3
if stop == 3:
return True
else:
return False
return True or False
Oct. 28, 2016
