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Three words solution in Clear category for Three Words by KacperBeisert
def checkio(words):
counter = 0
for word in words.split(' '):
if word[0].isdigit():
counter = 0
else:
counter += 1
if counter == 3:
return True
return False
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("Hello World hello") == True, "Hello"
assert checkio("He is 123 man") == False, "123 man"
assert checkio("1 2 3 4") == False, "Digits"
assert checkio("bla bla bla bla") == True, "Bla Bla"
assert checkio("Hi") == False, "Hi"
Dec. 4, 2015
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