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Without datetime module solution in Clear category for The Most Frequent Weekdays by ciel
def zeller(_y,m,d):
m+=1
if m<4: _y-=1;m+=12
y=_y//100
z=_y%100
return (5*y+z+y//4+z//4+13*m//5+d-1)%7
def leap(y):
if y%400==0: return True
if y%100==0: return False
return y%4==0
WDAY=['Monday','Tuesday','Wednesday','Thursday','Friday','Saturday','Sunday']
def most_frequent_days(y):
d=zeller(y,1,1)
r=[(d+6)%7]
if leap(y): r.append(d)
return [WDAY[d] for d in sorted(r)]
if __name__ == '__main__':
assert most_frequent_days(2399) == ['Friday'], "1st example"
assert most_frequent_days(1152) == ['Tuesday', 'Wednesday'], "2nd example"
assert most_frequent_days(56) == ['Saturday', 'Sunday'], "3rd example"
assert most_frequent_days(2909) == ['Tuesday'], "4th example"
March 22, 2016
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