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First solution in Clear category for The Highest Building by cardinalus
def highest_building(buildings):
for i in range(len(buildings)):
num = buildings[i].index(1) if 1 in buildings[i] else None
if num is not None:
break
return [num + 1, sum([1 for i in buildings if i[num]])]
if __name__ == '__main__':
print("Example:")
print(highest_building([
[0, 0, 1, 0],
[1, 0, 1, 0],
[1, 1, 1, 0],
[1, 1, 1, 1]
]))
#These "asserts" using only for self-checking and not necessary for auto-testing
assert highest_building([
[0, 0, 1, 0],
[1, 0, 1, 0],
[1, 1, 1, 0],
[1, 1, 1, 1]
]) == [3, 4], "Common"
assert highest_building([
[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 0],
[0, 0, 0, 1]
]) == [4, 1], "Cabin in the wood"
assert highest_building([
[1, 0, 0, 0, 0],
[1, 1, 0, 0, 0],
[1, 1, 1, 0, 0],
[1, 1, 1, 1, 0],
[1, 1, 1, 1, 1]
]) == [1, 5], "Triangle"
assert highest_building([
[0, 0, 0, 1, 0, 0, 0],
[0, 0, 1, 1, 1, 0, 0],
[0, 1, 1, 1, 1, 1, 0],
[1, 1, 1, 1, 1, 1, 1],
[1, 1, 1, 1, 1, 1, 1],
[1, 1, 1, 1, 1, 1, 1]
]) == [4, 6], "Pyramid"
print("Coding complete? Click 'Check' to earn cool rewards!")
July 4, 2021
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