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First solution in Clear category for Striped Words by zenjoesepp
import re
VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"
def checkio(text):
words = re.split('\W+',text)
cnt = 0
regexp = f'[{CONSONANTS}]?([{VOWELS}][{CONSONANTS}])*[{VOWELS}]?'
for w in words:
if len(w)>1 and re.fullmatch(regexp,w.upper()): cnt += 1
return cnt
#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
assert checkio("My name is ...") == 3, "All words are striped"
assert checkio("Hello world") == 0, "No one"
assert checkio("A quantity of striped words.") == 1, "Only of"
assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"
July 2, 2018
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