First clear solution for Striped Words by zenjoesepp - python coding challenges

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First solution in Clear category for Striped Words by zenjoesepp

import re
VOWELS = "AEIOUY"
CONSONANTS = "BCDFGHJKLMNPQRSTVWXZ"

def checkio(text):
    words = re.split('\W+',text)
    cnt = 0
    regexp = f'[{CONSONANTS}]?([{VOWELS}][{CONSONANTS}])*[{VOWELS}]?'
    for w in words:
        if len(w)>1 and re.fullmatch(regexp,w.upper()): cnt += 1
    return cnt

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    assert checkio("My name is ...") == 3, "All words are striped"
    assert checkio("Hello world") == 0, "No one"
    assert checkio("A quantity of striped words.") == 1, "Only of"
    assert checkio("Dog,cat,mouse,bird.Human.") == 3, "Dog, cat and human"

July 2, 2018

Comments:

frankiser on March 30, 2019, 8:07 p.m.
<p>Nice usage of regular expressions. I knew it was short with regexp, but did not find a solution.</p> <p>Statement after if-condition could be put on indented next line to increase readability. </p>

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