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Decoy solution in Clear category for Striped Words by MrPod
V = "AEIOUY"
C = "BCDFGHJKLMNPQRSTVWXZ"
def checkio(text):
a=['']
for i in text:
if i.isalpha():
a[~0]+='01'[i.upper() in V]
elif i in ',.!? ':
a.append('')
else:
a[~0]+='11'
return sum(len(i)>1 and i.find('00')+i.find('11')==-2 for i in a)
March 11, 2020
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