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Simple logic, build list of words and join in the end solution in Clear category for Speech Module by oLeBeLo
FIRST_TEN = ["one", "two", "three", "four", "five", "six", "seven",
"eight", "nine"]
SECOND_TEN = ["ten", "eleven", "twelve", "thirteen", "fourteen", "fifteen",
"sixteen", "seventeen", "eighteen", "nineteen"]
OTHER_TENS = ["twenty", "thirty", "forty", "fifty", "sixty", "seventy",
"eighty", "ninety"]
HUNDRED = "hundred"
def checkio(n):
words = []
u,d,c = int(n%10),int(n/10%10),int(n/100%10)
print(c,d,u)
if c:
words+=[FIRST_TEN[c-1],HUNDRED]
if d==1:
words+=[SECOND_TEN[u]]
else:
if d>1:
words+=[OTHER_TENS[d-2]]
if u>0:
words+=[FIRST_TEN[u-1]]
return " ".join(words)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(4) == 'four', "1st example"
assert checkio(133) == 'one hundred thirty three', "2nd example"
assert checkio(12) == 'twelve', "3rd example"
assert checkio(101) == 'one hundred one', "4th example"
assert checkio(212) == 'two hundred twelve', "5th example"
assert checkio(40) == 'forty', "6th example"
assert not checkio(212).endswith(' '), "Don't forget strip whitespaces at the end of string"
print('Done! Go and Check it!')
Oct. 20, 2019
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