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First solution in Clear category for Sort Array by Element Frequency by wingney
def frequency_sort(items):
lst=[]
sdict=dict((i,items.count(i)) for i in items)
sortdict=sorted(sdict.items(),key=lambda x:x[1], reverse=True)
for i in sortdict:
for j in range(i[1]):
lst.append(i[0])
return lst
if __name__ == '__main__':
print("Example:")
print(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob']))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
June 11, 2020
