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Counter neat solution solution in Clear category for Sort Array by Element Frequency by hodthegever
from collections.abc import Iterable
from collections import Counter
def frequency_sort(items: list[str | int]) -> Iterable[str | int]:
items_count = Counter(items)
return sorted(items_count.elements(), key = lambda x: items_count[x], reverse = True)
print("Example:")
print(list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])))
# These "asserts" are used for self-checking
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort([4, 6, 2, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 2, 2, 2, 6, 6]
assert list(frequency_sort(["bob", "bob", "carl", "alex", "bob"])) == [
"bob",
"bob",
"bob",
"carl",
"alex",
]
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("The mission is done! Click 'Check Solution' to earn rewards!")
Aug. 4, 2025
