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I think its pretty clear solution in Clear category for Sort Array by Element Frequency by bochikas
def frequency_sort(items):
unique_items = []
for item in items:
if item not in unique_items:
unique_items.append(item)
output = list()
while unique_items:
max_item = max(unique_items, key=items.count)
unique_items.remove(max_item)
output.extend([max_item] * items.count(max_item))
return output
if __name__ == '__main__':
print("Example:")
print(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4]))
# These "asserts" are used for self-checking and not for an auto-testing
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort(['bob', 'bob', 'carl', 'alex', 'bob'])) == ['bob', 'bob', 'bob', 'carl', 'alex']
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("Coding complete? Click 'Check' to earn cool rewards!")
July 15, 2021
