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Classic solution in 3rd party category for Sort Array by Element Frequency by PistoleroAlan
from typing import Iterable
from collections import Counter
import numpy as np
def frequency_sort(items: list[str | int]) -> Iterable[str | int]:
itemssort=[]
for x,f in Counter(items).most_common():
itemssort.extend(np.repeat(x,f))
return itemssort
print("Example:")
print(list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])))
# These "asserts" are used for self-checking
assert list(frequency_sort([4, 6, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 6, 6, 2, 2]
assert list(frequency_sort([4, 6, 2, 2, 2, 6, 4, 4, 4])) == [4, 4, 4, 4, 2, 2, 2, 6, 6]
assert list(frequency_sort(["bob", "bob", "carl", "alex", "bob"])) == [
"bob",
"bob",
"bob",
"carl",
"alex",
]
assert list(frequency_sort([17, 99, 42])) == [17, 99, 42]
assert list(frequency_sort([])) == []
assert list(frequency_sort([1])) == [1]
print("The mission is done! Click 'Check Solution' to earn rewards!")
Aug. 25, 2023
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