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First solution in Clear category for Similar Triangles by Kurush
from typing import List, Tuple
import math
Coords = List[Tuple[int, int]]
def rho(A, B):
return math.sqrt((A[0] - B[0]) ** 2 + (A[1] - B[1]) ** 2)
def similar_triangles(coords_1: Coords, coords_2: Coords) -> bool:
triangle1 = sorted([rho(coords_1[0], coords_1[1]), rho(coords_1[1], coords_1[2]), rho(coords_1[2], coords_1[0])])
triangle2 = sorted([rho(coords_2[0], coords_2[1]), rho(coords_2[1], coords_2[2]), rho(coords_2[2], coords_2[0])])
if triangle1[0] / triangle2[0] == triangle1[1] / triangle2[1] == triangle1[2] / triangle2[2]: return True
else: return False
if __name__ == '__main__':
print("Example:")
print(similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]))
# These "asserts" are used for self-checking and not for an auto-testing
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 2), (5, 0)]) is True, 'basic'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(3, 0), (4, 3), (5, 0)]) is False, 'different #1'
assert similar_triangles([(0, 0), (1, 2), (2, 0)], [(2, 0), (4, 4), (6, 0)]) is True, 'scaling'
assert similar_triangles([(0, 0), (0, 3), (2, 0)], [(3, 0), (5, 3), (5, 0)]) is True, 'reflection'
assert similar_triangles([(1, 0), (1, 2), (2, 0)], [(3, 0), (5, 4), (5, 0)]) is True, 'scaling and reflection'
assert similar_triangles([(1, 0), (1, 3), (2, 0)], [(3, 0), (5, 5), (5, 0)]) is False, 'different #2'
print("Coding complete? Click 'Check' to earn cool rewards!")
May 3, 2021
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