for f in str.isupper, str.islower: clear solution for Seven Segment by flpo - python coding challenges

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for f in str.isupper, str.islower: solution in Clear category for Seven Segment by flpo

segments = list(map(set, [
    'bc',
    'abged',
    'abgcd',
    'fbgc',
    'afgcd',
    'afgcde',
    'abc',
    'abcdefg',
    'abcdfg',
    'abcdef'
]))


def seven_segment(*args):
    r = 1
    for f in str.isupper, str.islower:
        lit, broken = ({s.lower() for s in segs if f(s)} for segs in args)
        r *= sum(lit <= s <= (broken | lit) for s in segments)
    return r

May 31, 2018

Comments:

Tinus_Trotyl on June 3, 2018, 12:01 p.m.
Btw, cool list of strings to list of sets conversion :)

Vladislav_Fyodorov on July 4, 2018, 9:04 a.m.
The traditional question: could you explain how that cycle works? Seems very intricate.

Vladislav_Fyodorov on July 4, 2018, 9:20 a.m.
It seems I understand how it works, but I don't quite get "if f(s)". Could you explain it?

Oksana_Antropova on May 4, 2019, 8:56 a.m.
`f(s)` becomes `str.isupper(s)` which is the same as `s.isupper()` for the first digit and `str.islower(s)` for the second. Both functions return a boolean value.

Different kind of sets

0 %

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