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First solution in Clear category for Second Index by Max0526
def second_index(text: str, symbol: str) -> [int, None]:
if text.count(symbol) < 2:
return None
if text.count(symbol) >= 2:
first = text.find(symbol, 0)
second = text.find(symbol, first+1)
return second
# second_index = lambda text, symbol: text.find(symbol, text.find(symbol) + 1) if text.count(symbol) >= 2 else None
if __name__ == '__main__':
print('Example:')
print(second_index("sims", "s"))
# These "asserts" are used for self-checking and not for an auto-testing
assert second_index("sims", "s") == 3, "First"
assert second_index("find the river", "e") == 12, "Second"
assert second_index("hi", " ") is None, "Third"
assert second_index("hi mayor", " ") is None, "Fourth"
assert second_index("hi mr Mayor", " ") == 5, "Fifth"
print('You are awesome! All tests are done! Go Check it!')
May 3, 2023
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