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First solution in Clear category for Second Index by GianniErrera
def second_index(text: str, symbol: str) -> [int, None]:
# first thing we find the substring that starts from the first occurrence of thew symbol
# and we store the number of chracters cut in a variable
if symbol in text:
characters_cut = text.index(symbol)+1
substring = text[text.index(symbol)+1:]
# then if there is a second occurrence we find its index
# and we add the numbers of characters cut from the original string
if symbol in substring:
return text[text.index(symbol)+1:].index(symbol)+ characters_cut
# no occurrence was found
return None
if __name__ == '__main__':
print('Example:')
print(second_index("sims", "s"))
# These "asserts" are used for self-checking and not for an auto-testing
assert second_index("sims", "s") == 3, "First"
assert second_index("find the river", "e") == 12, "Second"
assert second_index("hi", " ") is None, "Third"
assert second_index("hi mayor", " ") is None, "Fourth"
assert second_index("hi mr Mayor", " ") == 5, "Fifth"
print('You are awesome! All tests are done! Go Check it!')
Aug. 10, 2022
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