Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Roman Numerals by ikarus93
def checkio(n):
signs = ["M", "CM", "D", "CD", "C", "XC", "L", "XL", "X", "IX", "V", "IV", "I"]
nums = [1000, 900, 500, 400, 100, 90, 50, 40, 10, 9, 5, 4, 1]
roman = ""
while n > 0:
for i, num in enumerate(nums):
if num <= n:
roman += signs[i]
n -= num
break
return roman
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
Aug. 28, 2018
