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First solution in Clear category for Roman Numerals by alterGNU
def checkio(num):
l = [(1000, 'M'),(900, 'CM'),(500, 'D'),(400, 'CD'),(100, 'C'),(90, 'XC'),(50, 'L'),(40, 'XL'),(10, 'X'),(9, 'IX'),(5, 'V'),(4, 'IV'),(1, 'I')]
f = ''
for (n, r) in l:
(d, num) = divmod(num, n)
f += r * d
return f
Aug. 8, 2021
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