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dictbased solution in Clear category for Roman Numerals by Kirill__Gorin
def checkio(data):
roman={0: '', 1: 'I', 2: 'II', 3: 'III', 4: 'IV', 5: 'V',
6: 'VI', 7: 'VII', 8: 'VIII', 9: 'IX', 10: 'X', 20: 'XX',
30: 'XXX', 40: 'XL', 50: 'L', 60: 'LX', 70: 'LXX', 80: 'LXXX',
90: 'XC', 100: 'C', 200: 'CC', 300: 'CCC', 400: 'CD', 500: 'D',
600: 'DC', 700: 'DCC', 800: 'DCCC', 900: 'CM', 1000: 'M',
2000: 'MM', 3000: 'MMM', 4000: 'MMMM'}
nums=(1000, 100, 10, 1)
if data in roman:
return roman.get(data)
d=str(data).zfill(4)
line=''.join([roman.get(int(d[i])*nums[i]) for i in range(4)])
return line
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
June 7, 2018
