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Roman Numerals solution in Clear category for Roman Numerals by Druggist
def checkio(data):
result = ""
multiplicator = 5000
roman = ["M", "D", "C", "L", "X", "V", "I"]
for x in range(7):
multiplicator //= 5*((x + 1)%2) + 2*(x%2)
number = data // multiplicator
data -= number * multiplicator
for i in range(number):
result += roman[x]
if data >= 900 and data < 1000:
result += "CM"
data -= 900
elif data >= 400 and data < 500:
result += "CD"
data -= 400
elif data >= 90 and data < 100:
result += "XC"
data -= 90
elif data >= 40 and data < 50:
result += "XL"
data -= 40
elif data == 9:
result += "IX"
data -= 9
elif data == 4:
result += "IV"
data -= 4
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
Nov. 26, 2016
