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First solution in Clear category for Roman Numerals by 9maksim
def checkio(data):
num=""
a = [1000,900,500,400,100,90,50,40,10,9,5,4,1]
r = ["M","CM","D","CD","C","XC","L","XL","X","IX","V","IV","I"]
for j in range(len(a)):
num += data // a[j] * r[j]
data = data % a[j]
return num
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert checkio(6) == 'VI', '6'
assert checkio(76) == 'LXXVI', '76'
assert checkio(499) == 'CDXCIX', '499'
assert checkio(3888) == 'MMMDCCCLXXXVIII', '3888'
print('Done! Go Check!')
Nov. 25, 2019
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