First clear solution for Reverse Roman Numerals by thealfest1 - python coding challenges

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First solution in Clear category for Reverse Roman Numerals by thealfest1

def reverse_roman(r):
    number = 0
    d = {"M":1000, "CM":900, "D":500, "CD":400, "C":100, "XC":90, "L":50,
        "XL":40, "X":10, "IX":9, "V":5, "IV":4, "I":1}
    for key in sorted(list(d.keys()), key = len, reverse = 1):
        number += r.count(key) * d[key]
        r = r.replace(key, '')
    return number

Feb. 2, 2019

Mine

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