Enable Javascript in your browser and then refresh this page, for a much enhanced experience.
First solution in Clear category for Reverse Roman Numerals by Chocolater
NUMBERS = {'I': 1, 'V': 5, 'X': 10, 'L': 50, 'C': 100, 'D': 500, 'M': 1000}
def reverse_roman(roman_string):
result = 0
while roman_string:
if len(roman_string) > 1:
if NUMBERS[roman_string[-2]] < NUMBERS[roman_string[-1]]:
result += NUMBERS[roman_string[-1]] - NUMBERS[roman_string[-2]]
roman_string = roman_string[:-2]
continue
result += NUMBERS[roman_string[-1]]
roman_string = roman_string[:-1]
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert reverse_roman('VI') == 6, '6'
assert reverse_roman('LXXVI') == 76, '76'
assert reverse_roman('CDXCIX') == 499, '499'
assert reverse_roman('MMMDCCCLXXXVIII') == 3888, '3888'
print('Great! It is time to Check your code!')
Aug. 17, 2018
