1-liner works just as much as I can hope creative solution for Replace First by Stensen - python coding challenges

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1-liner works just as much as I can hope solution in Creative category for Replace First by Stensen

replace_first = lambda l: l[1%len(l):]+l[:1%len(l)] if not len(l)==0 else l

Sept. 20, 2020

Comments:

Phil15 on Nov. 9, 2020, 11:02 p.m.
I was just curious about "pure code" in the title. But so much to tell about this creative code. <pre class='brush: python'>"not len(l)==0" is equivalent to "l" "1%len(l) == (1 if len(l) > 1 else 0)" since len(l) > 0 but "1" is enough after that it becomes "l[1:]+l[:1] if l else l" but "l[1:]+l[:1]" is enough </pre>

Stensen on Nov. 9, 2020, 11:21 p.m.
So this answer would be like this surely, But I still don't know how I thought of it that way: Maybe I was fatigued, I think Was Just shitting all over my self I think I should better delete this shitty answer! <pre class='brush: python'>replace_first = lambda l: l[1:]+l[:1] if l else l </pre>

Stensen on Nov. 9, 2020, 11:23 p.m.
I am sorry for the bad WORDS but this script is a waste of your time and mine!

Phil15 on Nov. 10, 2020, 7:46 a.m.
Yeah you were probably tired. Put it in creative category, it has tricky creativity. And just to be clear, it would be `replace_first = lambda l: l[1:]+l[:1]`

Phil15 on Nov. 10, 2020, 2:22 p.m.
If you do not know, clicking edit button below (?) your solution, you can change category, and eventually title, not the code itself ^^.

Stensen on Nov. 10, 2020, 2:59 p.m.
First, I thought that this code isn't favorable & I've just ruined it all, But since you like I don't I have to thank you. I moved it to creative and certainly chained the title. I really appreciate your support and appreciation to this code.

Elementary

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