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First solution in Clear category for Probably Dice by eugene100372
def probability(dice_number, sides, target):
nums=range(1,sides+1)
d,d1={n:1/sides for n in nums},{}
for i in range(1,dice_number):
for key in d:
for n in nums:
d1[key+n]=d1.get(key+n,0)+d[key]/sides
d,d1=d1,{}
return round(d.get(target,0),4)
if __name__ == '__main__':
#These are only used for self-checking and are not necessary for auto-testing
def almost_equal(checked, correct, significant_digits=4):
precision = 0.1 ** significant_digits
return correct - precision < checked < correct + precision
assert(almost_equal(probability(2, 6, 3), 0.0556)), "Basic example"
assert(almost_equal(probability(2, 6, 4), 0.0833)), "More points"
assert(almost_equal(probability(2, 6, 7), 0.1667)), "Maximum for two 6-sided dice"
assert(almost_equal(probability(2, 3, 5), 0.2222)), "Small dice"
assert(almost_equal(probability(2, 3, 7), 0.0000)), "Never!"
assert(almost_equal(probability(3, 6, 7), 0.0694)), "Three dice"
assert(almost_equal(probability(10, 10, 50), 0.0375)), "Many dice, many sides"
March 10, 2020
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