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Popular Words solution in Clear category for Popular Words by nurme-ave
def popular_words(text: str, words: list) -> dict:
"""
Determine the popularity of certain words in the text.
Conditions:
- the words should be sought in all registers
- the search words are always indicated in the lowercase
- if the word isn’t found even once, it has to be returned in the dictionary with 0 (zero) value
"""
text = text.lower().split()
return {word: text.count(word) if word in words else 0 for word in words}
if __name__ == '__main__':
print("Example:")
print(popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']))
# These "asserts" are used for self-checking and not for an auto-testing
assert popular_words('''
When I was One
I had just begun
When I was Two
I was nearly new
''', ['i', 'was', 'three', 'near']) == {
'i': 4,
'was': 3,
'three': 0,
'near': 0
}
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May 10, 2020
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