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First solution in Clear category for Perfect Number Checking by freeman_lex
def is_perfect(n: int) -> bool:
sum_divisors = 1
for i in range(2, int(n**0.5) + 1):
if not n % i:
sum_divisors += i
# To avoid adding the same divisor twice for square numbers
if i != n // i:
sum_divisors += n // i
return sum_divisors == n
print("Example:")
print(is_perfect(3))
# These "asserts" are used for self-checking
assert is_perfect(6) == True
assert is_perfect(2) == False
assert is_perfect(28) == True
assert is_perfect(20) == False
assert is_perfect(496) == True
assert is_perfect(30) == False
assert is_perfect(8128) == True
assert is_perfect(100) == False
assert is_perfect(500) == False
assert is_perfect(1000) == False
print("The mission is done! Click 'Check Solution' to earn rewards!")
Sept. 26, 2023
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