First clear solution for Pawn Brotherhood by yonax - python coding challenges

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First solution in Clear category for Pawn Brotherhood by yonax

# migrated from python 2.7
def safe_pawns(pawns):
    board = {(ord(col) - ord('a') + 1, int(row)) for col, row in pawns}
    safe = lambda x_y: (x_y[0]-1, x_y[1]-1) in board or (x_y[0]+1, x_y[1]-1) in board
    
    return sum(1 for p in board if safe(p))

June 17, 2015

Comments:

rdknight on Feb. 15, 2016, 2:14 p.m.
<p>Elegant, good job</p>

Look up in the Dict()

0 %

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