Got it! clear solution for Pawn Brotherhood by maxim.poplavskiy - python coding challenges

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Got it! solution in Clear category for Pawn Brotherhood by maxim.poplavskiy

def safe_pawns(pawns):
    safe=set()
    di='.12345678.'
    abc='.abcdefgh.'

    for x in pawns:
        safe.add(abc[abc.index(x[0])-1]+di[di.index(x[1])+1])
        safe.add(abc[abc.index(x[0])+1]+di[di.index(x[1])+1])
    safe=safe&pawns
    
    return len(safe)

Feb. 10, 2015

Comments:

Evgenyy on April 21, 2015, 12:58 p.m.
I like your solution, i did it the same, but yours is simplier because of dots in di and abc.

trzyho on Sept. 13, 2018, 1:15 p.m.
great

bsquare on Sept. 13, 2019, 9:21 p.m.
Interesting solution!

Look up in the Dict()

0 %

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