First clear solution for Pawn Brotherhood by maciejmoscicki - python coding challenges

Enable Javascript in your browser and then refresh this page, for a much enhanced experience.

First solution in Clear category for Pawn Brotherhood by maciejmoscicki

def safe_pawns(pawns):
    lista=[]
    licznik=0
    
    for elementy in pawns:
        lista.append(elementy)
    rozmiar=len(lista)
    for element in lista:
        wierszglownego=int(element[1])
        kolumnaglownego=ord(element[0])
        #print(wierszglownego, kolumnaglownego)
        j=0
        liczbaznalezionych=0
        #print(rozmiar)
        while(j1):
            licznik=licznik-liczbaznalezionych+1
        liczbaznalezionych=0    
    return licznik   
        
if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 8, 2016

Look up in the Dict()

0 %

You ClassRoom Demo is Ready With the new tool CheckiO ClassRoom, you will be able to analyze your students' progress, have your own leaderboard, change missions order on the map, and so on.