First clear solution for Pawn Brotherhood by lexin13 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by lexin13

def safe_pawns(pawns):
    def is_safe(p, x):
        return abs(ord(p[0]) - ord(x[0])) == 1 and int(p[1]) - int(x[1]) == 1

    return len([p for p in pawns if any(is_safe(p, x) for x in pawns)])

March 18, 2016

Comments:

spizeck on Sept. 24, 2016, 7:32 a.m.
<p>I love your use of abs() to look to the left and right of the pawn at the same time.</p>

Look up in the Dict()

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