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chr(ord(+-1)) solution in Creative category for Pawn Brotherhood by k4ju
def safe_pawns(pawns):
result = 0
for pawn in pawns:
guards = [chr(ord(pawn[0])+i)+str(int(pawn[1])-1) for i in [-1,1]]
if guards[0] in pawns or guards[1] in pawns:
result += 1
return result
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Nov. 6, 2015
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