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Second-Pawn Brotherhood solution in Clear category for Pawn Brotherhood by iskenderunbtr
def safe_pawns(pawns: set):
x={"a":1,"b":2,"c":3,"d":4,"e":5,"f":6,"g":7,"h":8}
cord=list( (x[item[0]],int(item[1])) for item in pawns)
return sum( 1 if ( (item[0]-1,item[1]-1) in cord or (item[0]+1,item[1]-1) in cord) else 0 for item in cord)
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
Dec. 15, 2020
