First clear solution for Pawn Brotherhood by eldar_f - python coding challenges

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First solution in Clear category for Pawn Brotherhood by eldar_f

def safe_pawns(pawns):
    safe = 0
    for pawn in pawns:
        prev_col = chr(ord(pawn[0])-1)
        next_col = chr(ord(pawn[0])+1)
        next_row = str(int(pawn[1])-1)
        safe += bool(pawns.intersection({prev_col+next_row, next_col+next_row}))
    return safe


if __name__ == '__main__':
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Feb. 28, 2015

Comments:

gkozinakov on Jan. 20, 2020, 5:18 a.m.
You could name the variable "nextrow" -> "prevrow" :), like you did prev_col when it is -1 ... or my logic is different. But as long as it works it's okay.

max-belichenko on April 8, 2020, 2:39 p.m.
Good!

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