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First solution in Clear category for Pawn Brotherhood by eldar_f
def safe_pawns(pawns):
safe = 0
for pawn in pawns:
prev_col = chr(ord(pawn[0])-1)
next_col = chr(ord(pawn[0])+1)
next_row = str(int(pawn[1])-1)
safe += bool(pawns.intersection({prev_col+next_row, next_col+next_row}))
return safe
if __name__ == '__main__':
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Feb. 28, 2015
