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One line chess solution in Creative category for Pawn Brotherhood by bartosz_lyzwa
def safe_pawns(pawns):
return len(list(filter(lambda pawn:chr(ord(pawn[0])-1)+chr(ord(pawn[1])-1) in pawns or chr(ord(pawn[0])+1)+chr(ord(pawn[1])-1) in pawns,pawns)))
Oct. 19, 2017
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