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Pawn Brotherhood solution in Clear category for Pawn Brotherhood by azazel86
def safe_pawns(pawns):
count = 0
for p in pawns:
pd1 = chr(ord(p[0]) - 1) + str(int(p[1]) - 1)
pd2 = chr(ord(p[0]) + 1) + str(int(p[1]) - 1)
if pd1 in pawns or pd2 in pawns:
count += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
May 10, 2015
