First clear solution for Pawn Brotherhood by aieozn - python coding challenges

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First solution in Clear category for Pawn Brotherhood by aieozn

def safe_pawns(pawns):
    wer=['0','1','2','3','4','5','6','7','8','10'];
    hor=['x','a','b','c','d','e','f','g','h','z'];
    bezp=0;
    for i in range(10):
        for j in range(10):
            if ((hor[j]+wer[i]) in pawns):
                if ((hor[j-1]+wer[i-1]) in pawns):
                    bezp=bezp+1;
                elif((hor[j+1]+wer[i-1]) in pawns):
                    bezp=bezp+1;
            
    return bezp;

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Nov. 26, 2016

Look up in the Dict()

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