First clear solution for Pawn Brotherhood by a.a.v.worker - python coding challenges

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First solution in Clear category for Pawn Brotherhood by a.a.v.worker

def safe_pawns(pawns):
    count = 0
    pawns_index = [(ord(p[0]) - 97,int(p[1]) - 1) for p in pawns]
    for col,row in pawns_index:
        if ((col - 1,row-1) in pawns_index) or ((col + 1,row-1) in pawns_index):
            count += 1
    return count

Aug. 10, 2015

Look up in the Dict()

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