First clear solution for Pawn Brotherhood by Steven2222 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by Steven2222

def safe_pawns(pawns: set) -> int:
    """ Checks pawn safety state in one sided
    configuration of pawns.
    In: set of strings
    Out: int """
    
    # letter of element to ascii code, number to int
    # Calculate left and right position on lower row
    # Check if occupied
    
    safe = 0
    for element in pawns:
        #print('element is ' + str(element))
        letter = element[0]
        number = element[1]
        for i in (0, 2):
            #print(i)
            target = chr(ord(letter)-1+i)+str(int(number)-1)
            #print(target)
            if target in pawns:
                safe += 1
                #print (safe)
                break

    #print ('Dit is ' + str(safe))


    return safe

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

April 13, 2021

Comments:

rybld2 on June 6, 2021, 10:58 a.m.
<p>Clear and good</p>

Look up in the Dict()

0 %

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