First 3rd party solution for Pawn Brotherhood by Sara_Pinela - python coding challenges

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First solution in 3rd party category for Pawn Brotherhood by Sara_Pinela

import numpy as np

def safe_pawns(pawns):
    d  = {'a':0, 'b':1, 'c':2, 'd':3, 'e':4,'f':5, 'g':6, 'h':7}
    
    tablero = np.zeros((8,8))
    for coord in pawns:
        i = 8-int(coord[1])
        j=d[coord[0]]
        tablero[i,j]=1
    
    cont = 0
    f,c = tablero.shape
    for i in range(f):
        for j in range(c):
            if tablero[i,j] ==1:
                if tablero[i+1: i+2, j-1:j] ==1 or tablero[i+1: i+2, j+1: j+2] == 1:
                    cont += 1
                
    return cont
    
    

    
    

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Jan. 19, 2017

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