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Pawn Brotherhood solution in Clear category for Pawn Brotherhood by Poetakodu
def safe_pawns(pawns):
indeksy = set()
for p in pawns:
row = int(p[1]) - 1
col = ord(p[0]) - 97
indeksy.add((row, col))
count = 0
for row, col in indeksy:
is_safe = ( (row - 1, col + 1) in indeksy or (row - 1, col -1) in indeksy)
if is_safe:
count += 1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Oct. 23, 2016
