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First chr()+ord() solution in Clear category for Pawn Brotherhood by LeonidPK
def safe_pawns(pawns: set) -> int:
counter = 0
for pawn in pawns:
letter, back_row = pawn[0], str(int(pawn[1]) - 1)
# ord('a') == 93, chr(94) == 'b', chr(ord('b') - 1) == 'a'
left_back = chr(ord(letter) - 1) + back_row
right_back = chr(ord(letter) + 1) + back_row
if left_back in pawns or right_back in pawns:
counter += 1
return counter
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")
March 17, 2019
