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First solution in Clear category for Pawn Brotherhood by Kamil0320
def safe_pawns(pawns):
count=0
l=list(pawns)
for piece in l:
ch1=chr(ord(piece[0])-1)
ch2=chr(ord(piece[0])+1)
num=chr(ord(piece[1])-1)
if ch1+num in l or ch2+num in l:
count+=1
return count
if __name__ == '__main__':
#These "asserts" using only for self-checking and not necessary for auto-testing
assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1
Oct. 28, 2016
