First clear solution for Pawn Brotherhood by Kamil0320 - python coding challenges

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First solution in Clear category for Pawn Brotherhood by Kamil0320

def safe_pawns(pawns):
    count=0
    l=list(pawns)
    for piece in l:
        ch1=chr(ord(piece[0])-1)
        ch2=chr(ord(piece[0])+1)
        num=chr(ord(piece[1])-1)
        if ch1+num in l or ch2+num in l:
            count+=1
    return count

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert safe_pawns({"b4", "d4", "f4", "c3", "e3", "g5", "d2"}) == 6
    assert safe_pawns({"b4", "c4", "d4", "e4", "f4", "g4", "e5"}) == 1

Oct. 28, 2016

Look up in the Dict()

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