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Loops, loops, loops... solution in Clear category for Pawn Brotherhood by Happiness
def safe_pawns(pawns):
sPawns = 0
for p in pawns:
def1 = chr(ord(p[0]) - 1) + str(int(p[1]) - 1)
def2 = chr(ord(p[0]) + 1) + str(int(p[1]) - 1)
if def1 in pawns or def2 in pawns:
sPawns += 1
return sPawns
Feb. 14, 2015
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